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Thu Jan 30 07:39:47 EST 2020

testing rendez-vous

I have a test case, but QC found a problem when pulse sep is 0.

Ok the problem is in the writer.  I need a general principle to do
this.

Suppose ready is always high.  What is the output?
- If not acknowledged, repeat the last one
- If acknowledged, use next

Yes this is tricky because of the dependences on current and last
state.

I think it's best to express the separate cases explicitly.




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