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Mon Aug 17 17:51:41 EDT 2015

## Running in circles

I'm stuck. There is one very important thing I am just not seeing.
The monad contains the time behavior.
If this is the case, then every thing inside an 'm' has time behavior associated to it.
feedback :: s -> (s -> m (s, t)) -> m t
If the monad contains time behavior, then
s -> m (s, t)
means something like: given an initial state s, a sequence of s, t can be constructed.
So the monad IS a sequence.
If this is so, why is
add :: r t -> r t -> m (r t)
The result is not a sequence.
So looking from feedback, m is a sequence. Looking from add, m is
only sharing.
Makes no sense.

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